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TNPSC Aptitude Tips & Tricks, Model Question Paper


Quantitative Aptitude Tips & Tricks

With examples


Finding number of Factors 
To find the number of factors of a given number, express the number as a product of powers of prime numbers

In this case, 48 can be written as 16 * 3 = (24 * 3)
Now, increment the power of each of the prime numbers by 1 and multiply the result.
In this case it will be (4 + 1)*(1 + 1) = 5 * 2 = 10 (the power of 2 is 4 and the power of 3 is 1)
Therefore, there will 10 factors including 1 and 48. Excluding, these two numbers, you will have 10 – 2 = 8 factors.



Sum of n natural numbers
-> The sum of first n natural numbers = n (n+1)/2
-> The sum of squares of first n natural numbers is n (n+1)(2n+1)/6
-> The sum of first n even numbers= n (n+1)
-> The sum of first n odd numbers= n^2

Finding Squares of numbers
To find the squares of numbers near numbers of which squares are known
To find 41^2, Add 40+41 to 1600 =1681
To find 59^2, Subtract 60^2-(60+59) =3481

Finding number of Positive Roots
If an equation (i:e f(x)=0 ) contains all positive co-efficient of any powers of x , it has no positive roots then.
Eg: x^4+3x^2+2x+6=0 has no positive roots . 

Finding number of Imaginary Roots
For an equation f(x)=0 , the maximum number of positive roots it can have is the number of sign changes in f(x) ; and the maximum number of negative roots it can have is the number of sign changes in f(-x) .
Hence the remaining are the minimum number of imaginary roots of the equation(Since we also know that the index of the maximum power of x is the number of roots of an equation.)

Reciprocal Roots
The equation whose roots are the reciprocal of the roots of the equation ax^2+bx+c is cx^2+bx+a

Roots
Roots of x^2+x+1=0 are 1,w,w^2 where 1+w+w^2=0 and w^3=1

Finding Sum of the roots
For a cubic equation ax^3+bx^2+cx+d=o sum of the roots = - b/a sum of the product of the roots taken two at a time = c/a product of the roots = -d/a
For a biquadratic equation ax^4+bx^3+cx^2+dx+e = 0 sum of the roots = - b/a sum of the product of the roots taken three at a time = c/a sum of the product of the roots taken two at a time = -d/a product of the roots = e/a

Maximum/Minimum
-> If for two numbers x+y=k(=constant), then their PRODUCT is MAXIMUM if x=y(=k/2). The maximum product is then (k^2)/4
-> If for two numbers x*y=k (=constant), then their SUM is MINIMUM if x=y(=root(k)). The minimum sum is then 2*root (k). 
--> 

Inequalties
-> x + y >= x+y (stands for absolute value or modulus) (Useful in solving some inequations)
-> a+b=a+b if a*b>=0 else a+b >= a+b
-> 2<= (1+1/n)^n <=3 -> (1+x)^n ~ (1+nx) if x<<<1> When you multiply each side of the inequality by -1, you have to reverse the direction of the inequality.

Product Vs HCF-LCM 
Product of any two numbers = Product of their HCF and LCM . Hence product of two numbers = LCM of the numbers if they are prime to each other

AM GM HM
For any 2 numbers a>b a>AM>GM>HM>b (where AM, GM, HM stand for arithmetic, geometric, harmonic menasa respectively) (GM)^2 = AM * HM

Sum of Exterior Angles
For any regular polygon, the sum of the exterior angles is equal to 360 degrees hence measure of any external angle is equal to 360/n. (where n is the number of sides)
For any regular polygon, the sum of interior angles = (n-2)180 degrees
So measure of one angle in
Square-----=90
Pentagon--=108
Hexagon---=120
Heptagon--=128.5
Octagon---=135
Nonagon--=140
Decagon--=144

Problems on clocks
Problems on clocks can be tackled as assuming two runners going round a circle , one 12 times as fast as the other. That is, the minute hand describes 6 degrees /minute the hour hand describes 1/2 degrees / minute. Thus the minute hand describes 5(1/2) degrees more than the hour hand per minute.
The hour and the minute hand meet each other after every 65(5/11) minutes after being together at midnight. (This can be derived from the above).

Co-ordinates
Given the coordinates (a,b) (c,d) (e,f) (g,h) of a parallelogram , the coordinates of the meeting point of the diagonals can be found out by solving for [(a+e)/2,(b+f)/2] =[ (c+g)/2, (d+h)/2]

Ratio
If a1/b1 = a2/b2 = a3/b3 =.............., then each ratio is equal to (k1*a1+ k2*a2+k3*a3+..............) / (k1*b1+ k2*b2+k3*b3+..............) , which is also equal to (a1+a2+a3+............./b1+b2+b3+..........)

Finding multiples
x^n -a^n = (x-a)(x^(n-1) + x^(n-2) + .......+ a^(n-1) ) ......Very useful for finding multiples .For example (17-14=3 will be a multiple of 17^3 - 14^3)

Exponents
e^x = 1 + (x)/1! + (x^2)/2! + (x^3)/3! + ........to infinity 2 <>GP
-> In a GP the product of any two terms equidistant from a term is always constant.
-> The sum of an infinite GP = a/(1-r) , where a and r are resp. the first term and common ratio of the GP .

Mixtures
If Q be the volume of a vessel q qty of a mixture of water and wine be removed each time from a mixture n be the number of times this operation be done and A be the final qty of wine in the mixture then,
A/Q = (1-q/Q)^n
--> 

Some Pythagorean triplets:
3,4,5----------(3^2=4+5)
5,12,13--------(5^2=12+13)
7,24,25--------(7^2=24+25)
8,15,17--------(8^2 / 2 = 15+17 )
9,40,41--------(9^2=40+41)
11,60,61-------(11^2=60+61)
12,35,37-------(12^2 / 2 = 35+37)
16,63,65-------(16^2 /2 = 63+65)
20,21,29-------(EXCEPTION)

Apollonius theorem
Apollonius theorem could be applied to the 4 triangles formed in a parallelogram.

Function
Any function of the type y=f(x)=(ax-b)/(bx-a) is always of the form x=f(y) .

Finding Squares
To find the squares of numbers from 50 to 59
For 5X^2 use the formulae
(5X)^2 = 5^2 +X / X^2
Eg ; (55^2) = 25+5 /25 =3025
(56)^2 = 25+6/36 =3136
(59)^2 = 25+9/81 =3481
--> 

Successive Discounts
Formula for successive discounts
a+b+(ab/100)
This is used for successive discounts types of sums. Like 1999 population increases by 10% and then in 2000 by 5% so the population in 2000 now is 10+5+ (50/100) =+15.5% more that was in 1999 and if there is a decrease then it will be proceeded by a -ve sign and likewise.

Rules of Logarithms:
-> loga(M)=y if and only if M=ay
-> loga(MN)=loga(M)+loga(N)
-> loga(M/N)=loga(M)-loga(N)
-> loga(Mp)=p*loga(M)
-> loga(1)=0-> loga(ap)=p
-> log(1+x) = x - (x^2)/2 + (x^3)/3 - (x^4)/4 .........to infinity [ Note the alternating sign . .Also note that the ogarithm is with respect to base e ]


Read more tips & tricks visit  http://www.ias.org.in

General Aptitude model question paper: click here and download
 

All the Best.!!! @ tnpscnet.com
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1058 PGTRB Polytechnic - Study Material | TRB Notification Syllabus and Study Materials all in one Page | www.trb.nic.in last date: 07.07.2017

Teacher's Recruitment Board
Image result for trb

Post Graduate Lecturers in Polytechnique 

Notification - Syllabus - Study Materials - Hall Ticket - Result
all in one

Applications are invited only through online mode from eligible candidates upto 11.59 P.M on 07.07.2017 for the Direct Recruitment of Lecturers (Engineering / Non- Engineering) in Government Polytechnic Colleges for the year 2017-2018.

No. of Vacancies – 1058 Posts
Name of the Post: Lecturers (Engineering / Non Engineering) in Govt. Polytechnic Colleges
Salary: Scale of Pay Rs.15600-39100 + AGP Rs.5400/-

Important Dates:
Date of Notification: 16.06.2017
Application through online from: 17.06.2017
Last date to apply online: 07.07.2017
Date of Written Examination: 13.08.2017

Online Apply: Click here

PGTRB Polytechnic Lecturers Notification in English:


PGTRB Polytechnic Lecturers Notification in Tamil:
 


PGTRB Polytechnic Lecturers Syllabus:



Study Materials

Polytechnic Study Materials - Latest

NEW Polytechnic Study Materials 2017

Polytechnic - Computer Science - Study Material by Pace - English Medium Download Here
Polytechnic - English | Study Material - Test 2 by Kaviya - English Medium Download Here
Polytechnic - Computer Science | Study Material - Unit 8 by Kaviya - English Medium Download Here
Polytechnic - English | Study Material | Unit 9 (Topic 1) by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 10 (Topic 1) by Akshira - English Medium Download Here
Polytechnic - GK | Study Material | Unit 9 (Indian History) by Akshira - English Medium Download Here
Polytechnic - English | Study Material Test 1 by Kaviya - English Medium Download Here
Polytechnic - English | Study Material Unit 1 - Topic 10 by Kaviya - English Medium Download Here
Polytechnic - English | Study Material Unit 3 by Srimaan - English Medium Download Here
Polytechnic - Physics | Study Material by Karthi - English Medium Download Here
Polytechnic - Physics | Study Material by KS Academy - English Medium Download Here
Polytechnic - Chemistry | Study Material Unit 10 - Part 2 by D. Sukumar - English Medium Download Here 
Polytechnic - English | Study Material Unit 2 - Topic 1 by Akshiraa - English Medium Download Here 
Polytechnic - English | Study Material Unit1 - Topic 1 by Akshiraa - English Medium Download Here 
Polytechnic - English | Study Material | Unit 1.1 by Akshira - English Medium Download Here
Polytechnic - English | Study Material Unit 1 - Topic 2 by Akshiraa - English Medium Download Here 
Polytechnic - English | Study Material Unit 1 - Topic 3 by Akshiraa - English Medium Download Here 
Polytechnic - English | Study Material | Unit 3 by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 4 by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 5 (Topic 1) by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 4(Topic14) by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 8(Topic1) by Akshira - English Medium Download Here
Polytechnic - English | Study Material | Unit 7(Topic1) by Akshira - English Medium Download Here
Polytechnic - English | Study Material Unit 1 - Topic 1 by Srimaan - English Medium Download Here 
Polytechnic - English | Study Material Unit 1 - Topic 1 by Kaviya - English Medium Download Here
Polytechnic – English | Study Material by Kaviya - English Medium Download Here
Polytechnic - Physics | Study Material by Karthi - English Medium Download Here
Polytechnic - Physics | Study Material by Mr.D.Muthukumar - English Medium Download Here

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{CV - Result} TRB BT Assistants Direct Recruitment 2017 | 1114 B.T. Assistants and IEDSS TRB Recruitment Certificate Verification Final Result Published by TRB on 30.06.2017

Teachers Recruitment Board 
 College Road, Chennai-600006

TRB BT Assistants 2017 – CV Result 
Published on 30.06.2017

Direct Recruitment of B.T Assistants and B.T .Assistants (IEDSS) 2015-2016


PROVISIONAL SELECTION LIST  



Teachers Recruitment Board issued Notification for the Direct Recruitment of 1114 B.T.Assistants and B.T.Assistants (IEDSS) vide Notification No.2/2017, dated 27.04.2017
The Board released the list of Candidates in 1:1 ratio for Certificate Verification based on the details uploaded by the Candidates  through  the online updation process as well as the available Certificate Verification  data with TRB and by incorporating the list of previously  Selected candidates who did not join the service and who have now submitted application for consideration till 10.05.2017, duly following  communal rotation and other relevant rules in vogue.
             Certificate Verification was conducted from 08.06.2017 to 10.06.2017. After Certificate Verification, a Merit List is prepared from the eligible candidates based on the Current Certificate Verification details by awarding weightage marks as per G.O.MS.No.71School Education(TRB) dated 30.05.2014.  Provisional Selection list for the notified Vacancies will be prepared from the above said Merit list duly following communal rotation and other relevant rules in Vogue.
             This system of selection is purely provisional and is subject to the outcome of various Writ Petitions pending before the Hon’ble High Court of Madras and the decision of User Department on eligibility of Candidates.
             The appointment Order for the eligible candidates after Verifying and satisfying all conditions will be issued by the concerned appointing authority after due process and Verification.



Get Your CV Result: Clickhere 
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{Answer key} Download - PGTRB 2017 | TRB PG Assistant Exam 2017 Tentative Answer key | Exam Date: 02.07.2017


PGTRB 2017 Answer Key Download


TRB PG assistant examinassions held on 02.07.2017  consisted of a total of 150 multiple choice questions and the time duration given to student was 3 hours. The total 150 number of questions asked in the exam, 30 questions were from education methodology, 10 questions of general knowledge, and the major part was the 'main subject' paper which candidates had opted while applying.The main paper section carried 110 questions from subjects of candidates choice, one of these:
Tamil/ English/ Maths/ Physics/ Chemistry/ Commerce/ Zoology/ Botany/ Physical Education/ History/ Economics.
The question paper was issued only in English and Tamil. Official answer keys will be uploaded at www.trb.tn.nic.in while the unofficial answer keys will be uploaded here courtesy of sources. 










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Results {updated} - TNTET 2017 | Tamilnadu Teachers Eligibility Test 2017 Exam Results Declared Today | ww.trb.tn.nic.in TN TET Paper 1, Paper 2 Marks

TET Updates
TN TET 2017 Exam Results Announced 

Tamilnadu Teacher’s Recruitment Board (TRB) had conducted the Tamil Nadu TET Examination 2017 in two phases. Paper 1 examination was conducted on 29 April 2017 and Paper 2 examination was conducted on 30 April 2017. The TN TET 2017 results for both the papers (Paper I & Paper II) has been declared on July 1 2017



2,41,555 candidates appeared for Tamil Nadu Teacher Eligibility Test 2017 Paper I and 5,12,260 candidates appeared for the  Paper-II examination. 

On 2017 May 22, the answer keys were published on the website of the Teachers Recruitment Board and representations, objections, etc. were invited from the candidates within 5 days (upto May 27)

The TNTET Results have not been individually communicated to students. Now, candidates can check the Tamil Nadu TET results online in the official website of trb.tn.nic.in

The TET procedure was divided into sections. While Paper 1 aimed at selecting and recruiting teachers for classes 1 to 5th Standard.
Paper 2 aimed at selecting and recruiting teachers for classes 6 to 10th Standard (SSLC)
TRB Tamil Nadu TET Results – Check Paper 1, Paper 2 Score
Exam Organizer
Tamil Nadu Teacher Recruitment Board
Test
TNTET 2017
Exam Dates
29/04/2017, 30/04/2017
Paper I Candidates
2,41,555
Paper II Candidates
5,12,260
Result Status
Result Announcement
1st July 2017
Official Website
www.trb.tn.nic.in


Anticipated that around 7.53 lakh students appeared for the TNTET 2017 examination. The TN TET answer key was already released before the declaration of result. Candidates who have appeared for the examination were allowed to send in the key answer objections. All objections were received in written and should be enclosed with documentary proof.
TNTET Certificate 
Candidates would be expected to score 60% or more to be considered eligible. A 5% percent relaxation would be provided to candidates belonging to the categories of: BC, BCM, MBC, SC, SCA, ST and PWD. The certificates would be issued only if the candidates have passed the TET Examination Paper I and Paper II.
The TNTET certificate remains valid for 7 years from the date of issue. The TET certificate stands as one of the eligibility conditions for appointment and recruitment and it isn’t the sole arbiter of certification.


Steps to Check your TNTET 2017 Results
1. To receive the results, candidates would be required to go to the official website: www.trb.tn.nic.in

2. To click @ TNTET Results 2017

3. On clicking that alternate link, they would be required to log in
Your registered candidate name,
Application number and Date of birth (DOB)

4. after clicking Submit button to view their results online

**They should download a copy of their result for future references.


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PAN - AADHAAR Link | Easy steps to link your Pan number with Aadhaar number

HOW TO LINK PAN – AADHAAR

Aadhaar Self Service Update Portal Below the steps are help to link your Pan number to Aadhaar.

Two methods are available to income tax official site.
Method – 1: Correction of PAN and New Apply for PAN
Method – 2: Update Aadhaar to link with PAN (Aadhaar Self Service Update Portal)
If update or Correction in your Aadhaar submit necessary documents to upload.


11 லட்சம் பான் கார்டுகளை முடக்கிய மத்திய அரசு : உங்கள் பான் அட்டையின் நிலை என்ன தெரிந்து கொள்ளுங்கள்.
11 லட்சம் பான் கார்டுகளை முடக்கிய மத்திய அரசு : உங்கள் பான் அட்டையின் நிலை என்ன தெரிந்து கொள்ளுங்கள் | மத்திய அரசு சுமார் 11 லட்சம் பான் அட்டைகளை முடக்கியுள்ளது. இதுகுறித்த தகவல்களை நிதித்துறைக்கான மத்திய இணை அமைச்சர்சந்தோஷ் குமார் காங்வார் வெளியிட்டுள்ளார். ஒரு நபரின் பெயரிலேயே பலபான் அட்டைகள் வழங்கப்பட்டிருப்பது கண்டுபிடிக்கப்பட்டு அவற்றை மத்திய அரசு முடக்கியுள்ளது. இதுகுறித்து ராஜ்யசபாவில் எழுத்துபூர்வமாக பதிலளித்த மத்திய நிதித்துறை இணையமைச்சர் சந்தோஷ் குமார் கங்வார், "பான் கார்டு என்பது வரி விதிப்பில் மிக முக்கியமான ஒன்றாகவும், ஒரு நபர் மேற்கொள்ளும் அனைத்து நிதி பரிவர்த்தனைகளை ஒருங்கிணைப்பதாகவும் உள்ளது. ஒரு நபருக்கு ஒரு பான் கார்டு ஒதுக்கீடு என்பது வழிகாட்டி கொள்கை. ஆனால், ஒரே நபருக்கு ஏராளமான பான் கார்டுகள் ஒதுக்கப்பட்டிருந்தன. ஜூலை 27-ம் தேதி கணக்கீட்டின் படி, உயிருடன் இல்லாத நபர்அல்லது பொய்யான அடையாளம்கொண்டவர்களின் பெயர்களில் 1,566 பேருக்குப் போலி பான் கார்டுகள் ஒதுக்கப்பட்டிருந்தன. அவை அடையாளம் காணப்பட்டு நீக்கப்பட்டுள்ளன. இதுபோல, ஒட்டுமொத்தமாக 11,44,211 பான் கார்டுகள் அடையாளம் காணப்பட்டு நீக்கப்பட்டுள்ளன" என்றார். மேலும், உங்கள் ஆதார் அட்டை செயல்பாட்டில்தான் உள்ளதா என்பதை அறிந்துகொள்ள மத்திய அரசு வசதி செய்துள்ளது. உங்கள் ஆதார் அட்டை குறித்து அறிந்துகொள்ள, முதலில், https://incometaxindiaefiling.gov.in/e-Filing/Services/KnowYourJurisdictionLink.html என்ற Link-Click செய்யுங்கள். அடுத்ததாகத்திறக்கும் வலைப்பக்கத்தில் கேட்கப்பட்டிருக்கும் தகவல்களைத்(உங்கள் பெயர், துணைப்பெயர், பிறந்த தேதி, மொபைல் எண் ஆகியவற்றை) தகுந்த இடங்களில் நிரப்பவும். இதன்பின்னர் உங்களுக்குக் கிடைக்கும் ஓ.டி.பி-யை பதிவு செய்தால், உங்களின் பான் அட்டை குறித்த அத்தனை நிலவரங்களும் உங்களுக்குக் கிடைக்கும்.
உங்கள் ஆதார் எண்ணை பான் எண்ணுடன் இணையுங்கள்



 PAN – Aadhaar link: click here



Income Tax Department Notification




SMS to Link PAN AADHAAR

Another Method is also available to link your PAN to AADHAAR that is SMS on your Registered Mobile Number. following steps are explain to link,

Step 1: type <UIDPAN> space your Aadhaar number < xxxx xxxx xxxx> space your PAN < xxxxxxx >

Ex.| UIDPAN<SPACE><12 digit Aadhaar><Space><10 digit PAN>


Step 2: Send the number 567678 (or) 56161

Press Release:

The Hidnu Tamil and Dinakaran Daily Newspapers



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