{Bank Jobs} 200 Vacancy Post in Union Bank of India Recruitment 2017 | Specialist Officer Vacancies and Degree | Apply Online last date: 21.10.2017

Union Bank of India Recruitment 2017

GENERAL MANAGER (HR)

MUMBAI

www.unionbankofindia.co.in

200 Bank Officer Job Notification

Union Bank of India has Announced notification for the post of Specialist Officer (Credit Officers) for any degree. The detailed eligibility and application process are given below.

Invite online application for the interested and eligible candidates to apply the 200 vacancy of Specialist officer (Credit Officer) in Union Bank of India post at all over India last date for apply – 21.10.2017

Name of the vacancy posts details:

Specialist Officer (Credit Officer) - 200 posts; Salary – Scale of Pay Rs.31,705-45,950/- Per Month; Educational Qualification - Bachelor’s degree in any discipline with minimum 60% aggregate marks and Candidates having professional qualification like MBA (Finance) / CA/ ICWA/ CFA/ FRM/ CAIIB from a University / Institution/Board recognized by Govt. of India/approved; Experience: Post Qualification Work Experience in processing of credit proposals in officer cadre with any Scheduled Commercial Bank for a minimum period of two years immediately preceding the cut-off date of application as per this Notification is mandatory; Age Limit - The selected candidates will be Minimum age: 23 years, Maximum age: 32 years (As per government Policy).

Application Fee:

General/OBC Candidates Application Fee – Rs.600.00/-,

All other candidates (ST/SC/Ex-s/PWD) Application Fee –Rs.100.00

(Only intimation charges)

Selection Procedure:

The selection process is based on Online Exam,

Group Discussion and Personal Interview

Online Examination / Test:

The structure of the Online Written Examination, if conducted, will be online and will consist of the following tests:

Name of the Tests	No. of Questions and Maximum Marks
Reasoning	50 multiple choice questions carrying a total of 25 marks
Quantitative Aptitude	50 multiple choice questions carrying a total of 50 marks
Professional knowledge relevant to the post	50 multiple choice questions carrying a total of 100 marks
English Language	50 multiple choice questions carrying a total of 25 marks

                   

Total Duration of Examination will be of 120 minutes

Total 200 multiple choice questions carrying a total of 200 Marks

Personal Interview of 50 marks

EXAMINATION CENTERS:

The Online Examination, if conducted, may be tentatively held on 25.11.2017 at the following centers:

(a) Bengaluru

(b) Delhi

(c) Kolkata

(d) Lucknow

(e) Mumbai.

How to apply for the vacancy:

Follow the steps:-

Before applying online, candidates should:

1. Log on to careers page at official website www.unionbankofindia.co.in

2. Eligible candidates are advised to open Notification & application form

i. Scan their photograph and signature, ensuring that both conform to the required specifications given as Annexure-I with this notification.

ii. Keep the necessary details of Educational Qualification, Post Qualification Work Experience and other personal details handy for entering in the online application.

iii. Create a valid personal email ID, if not already done. The email ID should be kept alive for entire duration of the recruitment process. Under no circumstances, the applicant should share email ID with any other person. Third party email ID is not permitted.

Check the Details before Submitting and take a print out of Union Bank of India Recruitment 2017 application form

Important Dates:

Online Application from: 04.10.2017

Last date for apply online: 21.10.2017

Official Notification: Click Here to Download

Online application form: Click Here to Apply

Read More

{Study materials} IBPS PDFs | IBPS Officers Practice Sets All Topics | Model Paper, Previous Papers, Aptitude & Reasoning, English | Bank Common exam study materials in PDF format

IBPS Officers Practice Sets All Topics | Model Paper, Previous Papers, Aptitude & Reasoning, English | Bank Common exam study materials in PDF format available

Missing Di Capsule Based




Missing Di Capsule Based On New Pattern




PUZZLES & SYLLOGISMS CAPSULE




SYLLOGISMS CAPSULE




COMPUTER MCQ'S




PUZZLES CAPSULE




IBPS SO PDFs IBPS SO IT Officers Practice Sets All Topics




IBPS SO Marketing Officers Digest




IBPS SO Agricultural Officers Digest




IBPS SO IT Officers Digest




PRACTICE PAPERS - Practice Papers for IBPS PO




IBPS Clerical Practice Mock Papers




Model Paper - 2 for IBPS Exams




Model Paper - 3 for IBPS Exams




IBPS Clerk Previous Papers




Practice Question Paper One - Aptitude




Practice Question Paper One - Reasoning




Practice Question Paper One - English

Read More

TNPSC Aptitude Tips & Tricks, Model Question Paper

Quantitative Aptitude Tips & Tricks

With examples

Finding number of Factors 

To find the number of factors of a given number, express the number as a product of powers of prime numbers

In this case, 48 can be written as 16 * 3 = (24 * 3)

Now, increment the power of each of the prime numbers by 1 and multiply the result.

In this case it will be (4 + 1)*(1 + 1) = 5 * 2 = 10 (the power of 2 is 4 and the power of 3 is 1)

Therefore, there will 10 factors including 1 and 48. Excluding, these two numbers, you will have 10 – 2 = 8 factors.

Sum of n natural numbers

-> The sum of first n natural numbers = n (n+1)/2

-> The sum of squares of first n natural numbers is n (n+1)(2n+1)/6

-> The sum of first n even numbers= n (n+1)

-> The sum of first n odd numbers= n^2

Finding Squares of numbers

To find the squares of numbers near numbers of which squares are known

To find 41^2, Add 40+41 to 1600 =1681

To find 59^2, Subtract 60^2-(60+59) =3481

Finding number of Positive Roots

If an equation (i:e f(x)=0 ) contains all positive co-efficient of any powers of x , it has no positive roots then.

Eg: x^4+3x^2+2x+6=0 has no positive roots . 

Finding number of Imaginary Roots

For an equation f(x)=0 , the maximum number of positive roots it can have is the number of sign changes in f(x) ; and the maximum number of negative roots it can have is the number of sign changes in f(-x) .

Hence the remaining are the minimum number of imaginary roots of the equation(Since we also know that the index of the maximum power of x is the number of roots of an equation.)

Reciprocal Roots

The equation whose roots are the reciprocal of the roots of the equation ax^2+bx+c is cx^2+bx+a

Roots

Roots of x^2+x+1=0 are 1,w,w^2 where 1+w+w^2=0 and w^3=1

Finding Sum of the roots
For a cubic equation ax^3+bx^2+cx+d=o sum of the roots = - b/a sum of the product of the roots taken two at a time = c/a product of the roots = -d/a

For a biquadratic equation ax^4+bx^3+cx^2+dx+e = 0 sum of the roots = - b/a sum of the product of the roots taken three at a time = c/a sum of the product of the roots taken two at a time = -d/a product of the roots = e/a

Maximum/Minimum

-> If for two numbers x+y=k(=constant), then their PRODUCT is MAXIMUM if x=y(=k/2). The maximum product is then (k^2)/4

-> If for two numbers x*y=k (=constant), then their SUM is MINIMUM if x=y(=root(k)). The minimum sum is then 2*root (k). 

--> 

Inequalties

-> x + y >= x+y (stands for absolute value or modulus) (Useful in solving some inequations)

-> a+b=a+b if a*b>=0 else a+b >= a+b

-> 2<= (1+1/n)^n <=3 -> (1+x)^n ~ (1+nx) if x<<<1> When you multiply each side of the inequality by -1, you have to reverse the direction of the inequality.

Product Vs HCF-LCM 

Product of any two numbers = Product of their HCF and LCM . Hence product of two numbers = LCM of the numbers if they are prime to each other

AM GM HM

For any 2 numbers a>b a>AM>GM>HM>b (where AM, GM, HM stand for arithmetic, geometric, harmonic menasa respectively) (GM)^2 = AM * HM

Sum of Exterior Angles

For any regular polygon, the sum of the exterior angles is equal to 360 degrees hence measure of any external angle is equal to 360/n. (where n is the number of sides)

For any regular polygon, the sum of interior angles = (n-2)180 degrees

So measure of one angle in

Square-----=90

Pentagon--=108

Hexagon---=120

Heptagon--=128.5

Octagon---=135

Nonagon--=140

Decagon--=144

Problems on clocks

Problems on clocks can be tackled as assuming two runners going round a circle , one 12 times as fast as the other. That is, the minute hand describes 6 degrees /minute the hour hand describes 1/2 degrees / minute. Thus the minute hand describes 5(1/2) degrees more than the hour hand per minute.

The hour and the minute hand meet each other after every 65(5/11) minutes after being together at midnight. (This can be derived from the above).

Co-ordinates

Given the coordinates (a,b) (c,d) (e,f) (g,h) of a parallelogram , the coordinates of the meeting point of the diagonals can be found out by solving for [(a+e)/2,(b+f)/2] =[ (c+g)/2, (d+h)/2]

Ratio

If a1/b1 = a2/b2 = a3/b3 =.............., then each ratio is equal to (k1*a1+ k2*a2+k3*a3+..............) / (k1*b1+ k2*b2+k3*b3+..............) , which is also equal to (a1+a2+a3+............./b1+b2+b3+..........)

Finding multiples

x^n -a^n = (x-a)(x^(n-1) + x^(n-2) + .......+ a^(n-1) ) ......Very useful for finding multiples .For example (17-14=3 will be a multiple of 17^3 - 14^3)

Exponents

e^x = 1 + (x)/1! + (x^2)/2! + (x^3)/3! + ........to infinity 2 <>GP

-> In a GP the product of any two terms equidistant from a term is always constant.

-> The sum of an infinite GP = a/(1-r) , where a and r are resp. the first term and common ratio of the GP .

Mixtures

If Q be the volume of a vessel q qty of a mixture of water and wine be removed each time from a mixture n be the number of times this operation be done and A be the final qty of wine in the mixture then,

A/Q = (1-q/Q)^n

--> 

Some Pythagorean triplets:

3,4,5----------(3^2=4+5)

5,12,13--------(5^2=12+13)

7,24,25--------(7^2=24+25)

8,15,17--------(8^2 / 2 = 15+17 )

9,40,41--------(9^2=40+41)

11,60,61-------(11^2=60+61)

12,35,37-------(12^2 / 2 = 35+37)

16,63,65-------(16^2 /2 = 63+65)

20,21,29-------(EXCEPTION)

Apollonius theorem

Apollonius theorem could be applied to the 4 triangles formed in a parallelogram.

Function

Any function of the type y=f(x)=(ax-b)/(bx-a) is always of the form x=f(y) .

Finding Squares

To find the squares of numbers from 50 to 59

For 5X^2 use the formulae

(5X)^2 = 5^2 +X / X^2

Eg ; (55^2) = 25+5 /25 =3025

(56)^2 = 25+6/36 =3136

(59)^2 = 25+9/81 =3481

--> 

Successive Discounts

Formula for successive discounts

a+b+(ab/100)

This is used for successive discounts types of sums. Like 1999 population increases by 10% and then in 2000 by 5% so the population in 2000 now is 10+5+ (50/100) =+15.5% more that was in 1999 and if there is a decrease then it will be proceeded by a -ve sign and likewise.

Rules of Logarithms:

-> loga(M)=y if and only if M=ay

-> loga(MN)=loga(M)+loga(N)

-> loga(M/N)=loga(M)-loga(N)

-> loga(Mp)=p*loga(M)

-> loga(1)=0-> loga(ap)=p

-> log(1+x) = x - (x^2)/2 + (x^3)/3 - (x^4)/4 .........to infinity [ Note the alternating sign . .Also note that the ogarithm is with respect to base e ]

Read more tips & tricks visit  http://www.ias.org.in

General Aptitude model question paper: click here and download 

All the Best.!!! @ tnpscnet.com

Read More